Kiaria is 7 years older than Jay. Martha is twice as old as Kiaria. The sum of their three ages is 77. Find the ratio of Jay's age to Kiaria's age to Martha's age. Input note: the parts in your ratio need to add up to 77.

The ratio of Jay's age to Kiaria's age to Martha's age.

Jay : Kiaria : Martha

14 : 21 :42

Step-by-step explanation:

Let the ages be represented as:

Kiaria = x

Jay = y

Martha = z

Kiaria is 7 years older than Jay.

x = 7 + y

Making y the subject of the formula

y = x - 7

Martha is twice as old as Kiaria.

z =2x

The sum of their three ages is 77.

x + y + z = 77 Equation 1

Hence, we substitute in Equation 1

z = 2x

y = x - 7

x + x - 7 + 2x = 77

4x - 7 = 77

4x = 77 + 7

4x = 84

x = 84/4

x = 21

Solving for y

y = x - 7

y = 21 - 7

y = 14

z =2x

z = 2 × 21

z = 42

Hence:

Kiaria = x = 21

Jay = y = 14

Martha = z = 42

The ratio of Jay's age to Kiaria's age to Martha's age.

Jay : Kiaria : Martha

14 : 21 :42

answer: 2/4

step-by-step explanation:

.24

step-by-step explanation:

the probability is   .24

the first player had the highest probability of getting a silver marble

the game could be made fair by adding back the marble that was drawn after each draw