Use the counting principle to find the probability of choosing the 8 winning lottery numbers when the numbers are chosen at random from 0-9

The probability of choosing the 8 winning lottery numbers when the numbers are chosen at random from 0-9 is:

We know that there are total 10 numbers from 0-9

As all of the 8 numbers may repeat.

Hence, total number of ticket number possible are:10×10×10×10×10×10×10×10=10^8

Now the probability of choosing the 8 winning lottery numbers is given by:

                   Hence, the answer is:

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it