3. A heavy rainstorm dumps 1.0 cm of rain on a city 5 km wide and 8 km long in a 2-hour period. How many metric tons (1 metric ton

Complete question :

A heavy rainstorm dumps 1.0 cm of rain on a city 5 km wide and 8 km long in a 2-h period. How many metric tons (1 metric ton = 103 kg) of water fell on the city? (1 cm3 of water has a mass of 1 g = 10−3 kg.) How many gallons of water was this?

4 * 10^5 metric tonne

Step-by-step explanation:

Given that :

City dimension : 5km by 8km = 5*10^5 by 8*10^5 cm

Drop of rain = 1cm

Volume of rain within 2 hour period :

V = (5*10^5 * 8*10^5 * 1) cm³

V = 40 * 10^10 cm³

1cm³ = 1g

40 * 10^10 cm³ = 40 g

(40 * 10^10) * (10^-3) = 40*10^7 kg

1 metric tonne = 1 * 10^3 kg

x = 40*10^7 kg

x = (40 * 10^7) / 10^3

x = 40 * 10^(7 - 3) metric tonne

x = 40 * 10^4

x = 4 * 10^5 metric tonne

y + 11 = (1/4)(x + 16)

step-by-step explanation:

50-60=10

step-by-step explanation: