Bill can buy jags, jigs and jogs for $\$1$, $\$2$ and $\$7$ each, respectively. What is the largest number of jogs he can purchase if he must buy at least one of each item and will spend exactly $\$50$

6 jogs

Step-by-step explanation:

To spend exactly $50

Jags = $1

Jigs = $2

Jogs = $7

If he must buy atleast 1 of each and still spend exactly $50

Hence, the largest number of jogs he can buy can be modeled as :

First obtain the multiples of 7 up to 50

Multiple of 7 up to 50

7 : 7, 14, 21, 28, 35, 42, 49

If $49 is spent on jigs, then he won't be able to purchase jigs.

Hence, the largest amount he can spend on jogs is $42

Thus, he can buy $42 / $7 = 6 jogs

The $8 left can be spent on jigs and jags

1/4 because there is 4 grades.

$9.41

step-by-step explanation: