What postulate could prove these two triangles congruent? 1: SAS
2: ASA
3: AAS
Finish the congruence statement below:
1:INF
2:FIN
3:IFN

76%

step-by-step explanation:

24% are dogs and the remaining is 76% because 100-24=76

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .

answer:

the answer is b) divide by -4 on each side and flip the sign.

step-by-step explanation:

we first need to start by dividing. this is because it is a multiplication problem to start.

we also need to make sure we flip the sign because any time you multiply or divide by negative numbers, the sign must be flipped.