Lin runs 2 3/4 miles in 2/5 of an hour. Tlyer runs 8 2/3 miles in 4/3 of an hour. How long does it take for each of them to run 10 miles

Lin 1.454 h

Noah 1.54h

Step-by-step explanation:

From the above, we were given that;

Lin ran 2 3/4 miles in 2/5 an hour. Then, Noah ran 8 2/3 miles in 4/3 an hour

Speed of Lin

V = [(2 3/4)/(2/5)] mph

V = [(11/4)/(2/5)] mph

V = 6.875mph

Speed of Noah

V = [(8 2/3)/(4/3)] mph

V = [26/3)/(4/3))] mph

V = 6.5mph

The time taken by Lin to cover 10 miles

t = 10/6.875

t = 1.454h

The time taken by Noah to cover 10 miles

t = 10/6.5

t = 1.54h

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.