A(3,0) and B(-3,0) are the two fixed points Find the locus of a point P at which AB subtend a right angle at P

Step-by-step explanation:

Let's take a general point P(x,y). If there is a right angle at P then the slopes of the lines passing through AP and BP must be perpendicular.

Two lines of slopes m1 and m2 are perpendicular if:

m1*m2=-1

The slope of the line passing through P(x,y) and A(3,0) is:

The slope of the line passing through P(x,y) and B(-3,0) is:

Substituting in the equation:

Operating:

The locus is a circle centered at the origin with radius 3

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the 14th row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100