Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is

Step-by-step explanation:

We need to Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x

The equation in slope-intercept form is: where m is slope and b is y-intercept.

Finding Slope:

The both equations given are parallel. So, they have same slope.

Slope of given equation y= - 2/3x is m = -2/3

This equation is in slope-intercept form, comparing with general equation   where m is slope , we get the value of m= -2/3

So, slope of required line is: m = -2/3

Finding y-intercept

Using slope m = -2/3 and point (-3,5) we can find y-intercept

So, we get b = 3

Now, the equation of required line:

having slope m = -2/3 and y-intercept b =3

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is

Step-by-step explanation:

5 = –⅔[–3] + b

2

Parallel equations have SIMILAR RATE OF CHANGES [SLOPES], so –⅔ remains as is.

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step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn