In a right triangle the hypotenuse c is 13 cm long and leg a is 12 cm long. Right angle at vertex c. Calculate the length of the leg b.

5

Step-by-step explanation:

b² =c²-b²

b=√(13²-12²) (you square root 13 and 12 and minus it from each other)

b=169(13²)-144(12²)=25

b=√(25) (square root the answer)

Answer =5

i think it might be a but you might want a second opinion

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.