O A box contains 40 oranges, 12 of which are unripe. I pick one at random.
What is the probability that it is
a ripe
b unripe?

Step-by-step explanation:

Nø of sample space, n(s) = 40

nø of unripe oranges, n (u) = 12

no of ripe oranges, n (r) = 40 - 12 = 28

Now

The probability that it is ripe is, P(E)

= n(r) / n(s)

= 28 / 40

= 7 / 10

Also the probability that it is unripe is, P(E)

= n(u) / n(s)

= 12 / 40

= 3 / 10

Hope it will help :)❤

dont think so

step-by-step explanation:

3+3+3+2*2*2+29*12 = 365

step-by-step explanation: