Can anyone solve this question for me? Tommorrow is my test I really need to get goingI need some help?

m = 2, c = -8.

Step-by-step explanation:

The general form of a straight line equation is

y = mx + c    where m = the slope and c is the y-intercept.

We are given the line

y = 2x + 4

Comparing this with the general form we see that the slope of this line  = 2 and the y-intercept C is 4.

Now the given line y = mx + c is parallel to y = 2x + 4 which means that their slopes are the same so we conclude that m = 2.

Now we need to find the value of c which is the y intercept of y = mx + c.

Consider the points A and B:

A is the point where the line y = 2x + 4 intersects the x axis so y = 0 at this point , So substituting in the equation:

0 = 2x + 4

-4 = 2x

x = -2.

So the point A is (-2, 0)

B  is the point where y = 2x + c cuts the x axis so here y = 0:

0 = 2x + c

2x = -c

x = -c/2.

Now we are given that the 2 intercepts are 6 units apart, so:

-c/2 - (-2) = 6

-c/2 + 2 = 6

-c/2 = 4

-c = 8

c = -8.

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.

the answer to this is a. a^2 + b^2 = c^2