A) If a and B are the roots of the equation 3.x2 - 6x + 5 = 0, find the equation whose roots are a + B and
2÷a+B

Step-by-step explanation:

α and β are roots of 3x² - 6x + 5 = 0.

By Vieta's Formula,

we have αβ = 5/3 and α + β = 2.

To find the equation with roots α + β and 2/(α + β),

we find the Sum and Product of these roots.

=> Sum = (α + β) + 2/(α + β) = (2) + 2/(2) = 3.

=> Product = (α + β) * 2/(α + β) = 2.

Hence we have Ax² + Bx + C,

where -B/A = 3 and C/A = 2.

Simplest form is A = 1, B = -3, and C = 2.

Hence the equation with roots

α + β and 2/(α + β) is x² - 3x + 2.

answer: x

step-by-step explanation: