(5 pts) A quadratic function f is given by f(x) = ax2 + bx + c where a is not 0. Select all the statements that must be true about the graph of f.
a.
The y-intercept of the graph is at (0,c).
b.
The graph has an x-intercept at (c,0).
C.
When a < 0 the graph is open downward.
d.
The graph has two x-intercepts.
e.
If b = 0, then the vertex is on the y-axis.

Answers:

a) True. Plug in x = 0 and it leads to y = c. Therefore, the point (0,c) is on the parabola.b) False. Plug in y = 0 and apply the quadratic formula. One x intercept may sometimes be x = c, but it could easily be other values as well. Or perhaps you may not get any real number solutions at all. See part d) below.c) True. If a < 0, then the leading coefficient is negative. Overall, both endpoints will tend toward negative infinity to produce a parabola that opens downward.d) False. The quadratic may have one x intercept or it may not have any x intercepts at all. It depends on what the discriminant d = b^2 - 4ac is equal to. If d < 0, then we have no x intercepts. If d = 0, then we have exactly 1 x intercept. If d > 0, then we have two different x intercepts.e) True. The vertex's x coordinate is -b/(2a). If b = 0, then the x coordinate of the vertex is 0. The vertical line x = 0 is directly on top of the y axis.

The domain is 100 becuase i said so ok. jk its 00 jk again its r jk again and again its 75jk im always kiffing okaydbdbekufir83gc84vrudnmm as 8ehehenenrn vr 0eh339520252026ee6ee8e9