Find the area of a cement walkway of width 2 meters around a 50 m by 25 m pool.

9514 1404 393

  316 m²

Step-by-step explanation:

The centerline length of the walkway is 2×(52 m +27 m) = 158 m.

The area is the product of the walkway's centerline length and its width:

  A = (158 m)(2 m) = 316 m²

More detail on this approach

The centerlines of the long-side walkways are 25 m + 1 m + 1 m = 27 m apart. The centerlines of the short-side walkways are 50 m + 1 m + 1 m = 52 m apart.

The total length of the centerline is the perimeter of a 27 m by 52 m rectangle:

  P = 2(L+W) = 2(52 m +27 m) = 158 m

Usual approach

The area with the walkways is 54 m by 29 m = 1566 m². The area without the walkways is 50 m by 25 m = 1250 m². The difference is the area of the walkway, 1566 -1250 = 316 square meters.

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.