What are the solutions to the following system of equations? Select the correct answer below. y = x2 - 4x + 3
2x + y = 6
A) (-1,8) and (3,0)
B) (-1, 3) and (8,0)
C) (0,8) and (3, -1)
D) (3, 8) and (-1,0)

A

Step-by-step explanation:

we can conclude from the second equation that when

2x + y = 6 then y = 6 - 2x. so instead of y in the first equation we use 6 - 2x.

now the equation would look like this : 6 - 2x = x^2 - 4x + 3 .

then we bring everything to one side of the equation : x^2 - 2x - 3 .

now we'll have two results for x ( because x^2 - 2x - 3 = 0 has 2 answers )

one of them is -1 and other one is 3.

if we put them in the first equation we will have 8 and 0 for y.

so A is the answer

i would say the third one.

step-by-step explanation: liner would mean in a line and the only one that doesn't look like it's even thinking about forming a line would be the third one

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.