For a fundraiser, a group plans to sell granola bars and bottles of water at the same prices as described in Part A. The group wants the income from the fundraiser to be at least $150. Choose the inequality to show the number of granola bars x and the number of bottles of water y that must be sold.

Incomplete question. The missing part read;

Ten granola bars and twelve bottles of water cost $23. Five granola bars and four bottles of water cost $10.

Options:

A. 1.4x + 0.75y > 150

B. 1.4x + 0.75y ≥ 150

C. 1.4x + 0.75 < 150

D. 1.4x + 0.75 ≤ 150

B. 1.4x + 0.75y ≥ 150

Step-by-step explanation:

Remember, from the question we are told that the group wants the income from the fundraiser to be at least $150, meaning, they are not against having an income above $150 from the fundraiser, but a minimum of at least that amount.

Hence, among all the listed options, the correct inequality sign to represent the number of granola bars 'x' and the number of bottles of water 'y' that must be sold is the ≥  (equal to or greater than sign).

b

step-by-step explanation:

p = 6s

step-by-step explanation: