A football team scored 3 touchdowns, 3 extra points, and 4 field goals. Write an expression to represent the total points the football team scored. Use t to represent the number of points for a touchdown Use e to represent the number of points for the extra point Use f to represent the number of points for a field goal Write the equation using the "WIRIS editor" button

The sum of the points the team has from different point gaining options

give the total number of points the team scores.

Reasons:

The number of touchdowns by the football team, t = 3

Number of extra points by the football team, e = 3

Number of field goals by the team, f = 4

Therefor, the total number of points, P = 3·t + 3·e +4.f

The specified editor is an equation editor, which can be used to write mathematical equations.

Using an equation editor, we have;

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The answer is below

Step-by-step explanation:

A football team scored 3 touchdowns, 3 extra points, and 4 field goals.  

a. Write an expression to represent the total points the football team scored.  

b. Write another expression that is equivalent to the one written above.  

c. If each touchdown is worth 6 points, each extra point is 1 point, and each field goal is 3 points, how many total points did the team score?  

Solution:

a) Let t represent the number of points for a touchdown, e represent the number of points for the extra point and f represent the number of points for a field goal.

Total points = 3(t) + 3(e) + 4(f) = 3t + 3e + 4f

b) Total points = 3t + 3e + 4f   OR

Total points = t + t + t + e + e + e + f + f + f + f  OR

Total points = 3(t + e) + 4f

c) Total points = 3(t + e) + 4f = 3(6 + 1) + 4(3) = 3(7) + 4(3)

Total points = 21 + 12 = 33 points

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.