The equation of a line in slope-intercept form through the point (3, -4) and had a slope of 6

The equation of a line in slope-intercept form through the point (3, -4) and had a slope of 6 will be:

Step-by-step explanation:

Given

We know that the slope-intercept form of the line equation

y = mx+b

where

substituting m = 6 and the point (3, -4) in the slope-intercept form of the line equation  to determine the y-intercept b

y = mx+b

-4 = 6(3) + b

-4 = 18 + b

switch sides

b = -4 - 18

b = -22

now substituting m = 6 and the b = -22 in the slope-intercept form of the line equation

y = mx+b

y = 6x + (-22)

y = 6x - 22

Therefore, the equation of a line in slope-intercept form through the point (3, -4) and had a slope of 6 will be:

x = 12

y = 15

step-by-step explanation:

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.