OK PLEASE HELP ME. IVE BEEN TRYING TO REMEMBER HOW TO SOLVE THIS BUT IM FIND IT IT REALLY DIFFICULT Quadrilateral JKLM has vertices J(–7, –2), K(–2, –2), L(–3, –4), and M(–6, –4). Find the midpoints of each of the sides JM and KL.

Step-by-step explanation:

X-value of Midpoint of J(-7, -2) and M(-6, -4)

= [(-7) + (-6)] / 2 = -6.5.

Y-value of Midpoint of J(-7, -2) and M(-6, -4)

= [(-2) + (-4)] / 2 = -3.

X-value of Midpoint of K(-2, -2) and L(-3, -4)

= [(-2) + -3)] / 2 = -2.5.

Y-value of Midpoint of K(-2, -2) and L(-3, -4)

= [(-2) + (-4)] / 2 = -3.

We have (-6.5, -3) and (-2.5, 3).

The correct answer is Option D.

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

c) yes, because of asa or aas