To the nearest tenth, what is the perimeter of the triangle with vertices at (−2, 3), (3, 6), and (2, −2)?

The perimeter of triangle = 20.3

Step-by-step explanation:

We need to find perimeter of the triangle with vertices at (−2, 3), (3, 6), and (2, −2)

The formula used to find perimeter is:

First we need to find length of each side using distance formula:

Find distance between (−2, 3), (3, 6)

We have:

Putting values and finding distance

So, The distance between (−2, 3), (3, 6) is 5.83

Find distance between (3, 6),(2,-2)

We have:

Putting values and finding distance

So, The distance between (3, 6),(2,-2) is 8.06

Find distance between (-2,3),(2,-2)

We have:

Putting values and finding distance

So, The distance between (-2, 3),(2,-2) is 6.40

So, The length of side 1 = 5.83

The length of side 2 = 8.06

The length of side 3 = 6.40

The perimeter of triangle will be:

So, The perimeter of triangle = 20.3

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.

i think the length is 12 and the width is 17