Ben uses a compass and a straightedge to construct ∠DEF ≅ ∠ABC, as shown below: Which statement best explains why Ben uses the width BI to create the arc JK from point E?

A ∠DEF ≅ ∠ABC when BH = EK, BI = JK, and HI = EJ.
B BI = JK when ∠DEF ≅ ∠ABC.
C BI = EJ when ∠DEF ≅ ∠ABC.
D ∠DEF ≅ ∠ABC when BH = EJ, BI = EK, and HI = JK.

Choice D

∠DEF ≅ ∠ABC when BH = EJ, BI = EK, and HI = JK.

Explanation:

Effectively what Ben is doing is ensuring that

are the three congruent corresponding sides. This is by construction. After those constructions, he would use SSS to prove the triangles congruent. Lastly, he can then say angle DEF is congruent to angle ABC due to CPCTC.

CPCTC = corresponding parts of congruent triangles are congruent.

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.

oof cheaters cheat because they’re lazy that’s why i cheat xd

: )

step-by-step explanation: