Two submarines began dives in the same vertical position to meet at a designated point. If one submarine was on a course approximated by the equation x + 4y = -14 and

the other was on a course approximated by the equation x + 3y = -8, at what location would they meet?

(10, -6)

Step-by-step explanation:

The solution of the system of the equations given would be the location that they would both meet.

Let's solve:

x + 4y = -14 › Eqn. 1

x + 3y = -8 › Eqn. 2

Subtract Eqn. 2 from Eqn. 1

y = -6

Substitute y = -6 into Eqn. 1.

x + 4y = -14 › Eqn. 1

x + 4(-6) = -14

x - 24 = -14

x = -14 + 24 (addition property of equality)

x = 10.

The answer is: (10, -6)

a

explanation:

yo answer should be 6 if im not mistaken

step-by-step explanation: