A manufacture of spark plugs how's it going producing less than 2% affective ones. Of the last 8000 spark plugs, 13 were defective. a. What is the experimental probability that the next sparkplug will be defective? b. Did the manufacture reach his goal? Explain.

P = 0.001625

yes, it did

Step-by-step explanation:

given data

affective ones = 2%

spark plugs = 8000

defective = 13

to find out

experimental probability that the next sparkplug will be defective and Did the mannufacturer reach its goal

solution

we know that there are 13 are defective out of 8000

so P = 13 ÷ 8000

P = 0.001625

so  that P( the next sparkplug will be defective) is = 0.001625

and

yes, we mannufacturer to reach goal

because 0.001625 < .02

So, the goal is reached as the experimental probability is less than 2%

b

step-by-step explanation:

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11