The track is 9.76 m wide all the way around. What is the distance around the outside of the track? Explain or show your reasoning.

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c

current in the circuit at time t is /, then the power delivered to the resistor is

step-by-step explanation:

1/8 is left? add a bit more info plz