1. a rectangular room measures 10 feet by 12 feet. What is the area of the room? 2. What is the area of a rectangle with a base of 6 inches and height of 10 inches?

3. Travis is planting a rectangular garden that is 5 feet by 12 feet. One bag of soul covers 6 square feet. How many bags of soil does he need to cover the whole garden?

PLEASE HELP! PLEASE HELP!

Answers:

Explanation:

For problems 1 and 2, we just multiply the base and height. This is the same as multiplying the length and width.

So in problem 1 we have 10*12 = 120 square feet. In problem 2 we have 6*10 = 60 square inches.

Problem 3 follows the same idea, but we do a bit more work. The area of the garden is 5*12 = 60 square feet.

Let's say x is the number of bags needed.

1 bag covers 6 square feet

2 bags cover 12 square feet

and so on

x of those bags cover 6x square feet. The x is just a placeholder for a number. Specifically, a positive whole number.

The expression 6x represents how much area that can be covered by x bags. We want to cover 60 square feet.

The equation we need to solve is 6x = 60. Doing so leads to x = 10 after dividing both sides by 6.

So this means Travis needs 10 bags.

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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