Plz help lol
(12221×222) ×+212%234\/()231331783)2343#23=22+× 233)1(23€£÷÷) =

(c) 24 (d) 2 -4 (e) 22 2 1.25 0

Step-by-step explanation:

Problem 1.1 (10 Points) Let 21 2j, and 23 j. Find the value of each of the following 3 4j, 22 expressions and give your answers in rectangular form z t jy. (a) 132122 (b) 321 421 (c) (21)3 (Note that superscript denotes conjugation.) 222 21 (d) 22 (e) 2223 Problem 1.2 (10 Points) (a) Find real numbers r and y such that 5z -3y j(5y z) 4. (b) Show that any complex number z can also be expressed as z e 2"* k 0, 1,2, 3. Problem 1.3 (10 Points) Express each of the following complex numbers in polar form. a) 2 2V3 (c) 1 j j2 7 4j (d) 3-2j (e) Problem 1.4 (10 Points) Use the results from Problem 1.2 (b) above to find all roots of the following complex numbers and plot your results in the complex plane. (a) 1 (Hint: there are 5 different answers and one is 2 (b) 23 (1 -j) (Hint: there are 3 different answers. (c) 24 (d) 2 -4 (e) 22 2 1.25 0

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!