A line passes through the points (-8, 7) and (-11,-11). Find the value of a such 1 point that the point (-7,a) lies on the line. a=
Your answer

a=12

Step-by-step explanation:

we need the slope of this line. Find it with the slope formula

m= y2-y1 / x2-x1    with the points given p1=(-8,7)  and p2=(-11,-11)

m=-11-7 / -11-(-8)                                               (x1,y1)               (x2,y2)  

m= -18 /-11+8

m= -18 / - 3

m= 6

next plug in one of the point into the point-slope formula [y-y1=m(x-x1)]

y-7=6(x-(-8))  ( simplify this towards the slope intercept form [y=mx+b]

y-6=6(x+8)

y-6=6x+48

y=6x+54

now we can plug in our point of (-7,a) to find what a is

a=6(-7)+54

a=-42+54

a=12

:)

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation:

1/8 is left? add a bit more info plz