An osprey flying horizontally 100 feet above a lake spots a fish below. It tilts its flight path downward by 45°. If the osprey is diving at 45 mph, at what rate is its altitude changing (rounded to the nearest foot per second)?

the rate at which its altitude is changing is -47 ft/s

Step-by-step explanation:

Given that;

ds/dt = 45 mph =  45 × 5280/3600 = 66 ft/sec

no we have to determine dx/dt

so

cos∅ = dx/dt / ds/dt

cos45° = dx/dt / 66  

dx/dt = 0.7071 × 66

dx/dt = 46.6686 ≈ 47 ft/s ( as altitude is decreasing, its negative - )

so the rate at which its altitude is changing is -47 ft/s

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.