i’ll give you all my points that i have and rate you good if you answer these three questions before 3:00pm est. if f(x)=8-5x, find each value. one is f(4c), the second question is f(2-k), and the third is f(4p+3)

Ok so to start you plug in what’s in the parentheses for x

4c=8-5(4c)
2-k=8-5(2-k)
4p+3=8-5(4p+3)

In the first one you distribute the -5
4c=8-20c
Then add 20c to both sides
24c=8
And divide by 24
C=8/24 or 1/3

Distributing the -5 on the second one gets you
2-k=8-10+5k
Then you combine like terms
2-k=-2+5k
Subtract 5k from both sides
2-6k=-2
Subtract 2 from both sides
-6k=-4
Divide by -6
K=4/6 or 2/3

and lastly the equation is 4p+3=8-5(4p+3)

So you distribute -5
4p+3=8-20p-15
Combine like terms
4p+3=-20p-7
Add 20p to both sides
24p+3=-7
Subtract 3 from both sides
24p=-10
And then divide by 24
P= -10/24 or -5/12

Answer: the correct answer is 10step-by-step explanation: let the number be n, then the expression becomes,then“twelve more than the quotient of a number and two, decreased by four” iswhen n=4,we substitute 4 whetever we see n to get,we simplify to obtain,we further simplify to get,therefore the correct answer is c.