What's the sum of an infinite geometric series if the first term is 156 and the common ratio is 2∕3?

468

Step-by-step explanation:

Formula for infinite sum of geometric series is;

S_∞ = a1/(1 - r)

Where;

a1 is first term

r is common ratio

We are given;

a1 = 156

r = ⅔

Thus;

S_∞ = 156/(1 - ⅔)

S_∞ = 156/(⅓)

S_∞ = 468

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x

c

step-by-step explanation: