subject
Mathematics, 06.01.2021 17:10 jumana3

In photo, please help I am timed!!


In photo, please help I am timed!!

ansver
Answers: 2

Another question on Mathematics

question
Mathematics, 21.06.2019 16:10
To find the extreme values of a function f(x.y) on a curve x-x(t), y y(t), treat f as a function of the single variable t and use the chain rule to find where df/dt is zero. in any other single-variable case, the extreme values of f are then found among the values at the critical points (points where df/dt is zero or fails to exist), and endpoints of the parameter domain. find the absolute maximum and minimum values of the following function on the given curves. use the parametric equations x=2cos t, y 2 sin t functions: curves: i) the semicircle x4,y20 i) the quarter circle x2+y-4, x20, y20 b, g(x,y)=xy
Answers: 2
question
Mathematics, 21.06.2019 23:00
Ineed to know the ordered pairs for this equation i need the answer quick because it’s a timed test
Answers: 3
question
Mathematics, 22.06.2019 00:00
Aspacecraft can attain a stable orbit 300 kilometers above earth if it reaches a velocity of 7.7 kilometers per second. the formula for a rocket's maximum velocity v in kilometers per second is vequalsminus0.0098tplusc ln upper r, where t is the firing time in seconds, c is the velocity of the exhaust in kilometers per second, and r is the ratio of the mass of the rocket filled with fuel to the mass of the rocket without fuel. find the velocity of a spacecraft whose booster rocket has a mass ratio of 20, an exhaust velocity of 2.1 km/s, and a firing time of 15 s. can the spacecraft achieve a stable orbit 300 km above earth?
Answers: 3
question
Mathematics, 22.06.2019 02:00
87.5% , 100% , 83.33 , 93.33% , 100% , 82.5% are all the academic points i've gotten this quarter. what's my final grade?
Answers: 1
You know the right answer?
In photo, please help I am timed!!
...
Questions
question
Mathematics, 11.12.2020 01:00
question
Mathematics, 11.12.2020 01:00
question
Mathematics, 11.12.2020 01:00
question
History, 11.12.2020 01:00