Write the equation of the line containing the points (2,6)(2,6)and(5,0)(5,0)
. Do not include spaces in your answers. Use the forward slash (i. e. "/") for all fractions (e. g. -1/2 is the same as −12−12)
=

Step-by-step explanation:

Given the coordinate points (2, 6) and (5, 0)

We are to find the equation of the line passing through the points

The standard form of the equation is expressed as y = mx+c

m is the slope

c is the y intercept

Get the slope

m = y2-y1/x2-x1

m = 0-6/5-2

m = -6/3

m = -2

Get the intercept

Substitute m = -2 and the point (5, 0) into the equation y = mx+c

0 = -2(5) + c

0 = 10 + c

c = 10

Get the equation

Recall that y = mx+c

y = -2x + 10

Hence the required equation is y = -2x + 10

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: