Find the perimeter of a isosceles right triangle having area of 200 CM square

The perimeter of the isosceles right triangle is 68.28 cm.

Step-by-step explanation:

Given;

area of the isosceles right triangle, A = 200 cm²

let the two equal sides of the triangle = base (b) and height (h)

Area of the isosceles right triangle is calculated as;

let the hypotenuse side of the isosceles right triangle = c

c² = b² + h²

c² = 20² + 20²

c² = 800

c = √800

c = 28.28 cm

The perimeter of the isosceles right triangle is calculated as;

P = b + h + c

P = 20 cm + 20 cm + 28.28 cm

P = 68.28 cm

Therefore, the perimeter of the isosceles right triangle is 68.28 cm.

what statement? is there an image?

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: