Find the equation of the line described. Perpendicular to y = 3x + 6; passing through the point (4,5).
The line equation is y =

y = - x +

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x + 6 ← is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

= - = - , thus

y = - x + c ← is the partial equation

To find c , substitute (4, 5) into the partial equation

5 = - + c ⇒ c = 5 + =

y = - x + ← equation of perpendicular line

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2