Question Janine determines that the total resistance in her circuit is 80 ohms. Using the inverse equation modeling this situation, find the resistance of the second lightbulb.

The resistance of the second lightbulb is ohms.

A.120

B.300

C.240

D.40

40

Step-by-step explanation:

To find the The resistance of the second lightbulb goes thus:

We use the formula:

t = 120r /r + 20

Since the total resistance in her circuit is 80ohms, this is denoted by t. We would then find r. This would be:

80 = 120r / r + 20

Cross multiply

80(r + 20) = 120r

80r + 1600 = 120r

Collect like terms

120r - 80r = 1600.

40r = 1600.

r = 1600/40

r = 40

240

Step-by-step explanation

Just substitute 80 in for t in the inverse equation. The inverse equation is r = -120t/t-120 so if you substitute 80 in for t it would become -9600/-40   and dividing that will get you 240.

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step-by-step explanation: