Mathematics, 04.01.2021 19:40 pinapunapula

The daily output at a plant manufacturing chairs is approximated by the function

f(L, K) = 453KL 3/5 chairs

where L is the size of the labor force measured in hundreds

of worker-hours and K is the daily capital investment in

thousands of dollars. If the plant manager has a daily budget

of $13,000 and the average wage of an employee is $9.00

per hour, what combination of worker-hours (to the nearest

hundred) and capital expenditures (to the nearest thousand)

will yield maximum daily production?

Answers: 1

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Answers

Answer from: theonefreshmen

Complete Question

The daily output at a plant manufacturing chairs is approximated by the function

$f(L,K) = 45\sqrt[3]{K}L^3^/^5$ chairs

where L is the size of the labor force measured in hundreds

of worker-hours and K is the daily capital investment in thousands of dollars. If the plant manager has a daily budget of $13,000 and the average wage of an employee is $9.00 per hour, what combination of worker-hours (to the nearest hundred) and capital expenditures (to the nearest thousand) will yield maximum daily production?

a)200 worker-hours and $9000 in capital expenditure

b)1100 worker-hours and $3000 in capital expenditure

c)500 worker-hours and $8000 in capital expenditure

d)900 worker-hours and $5000 in capital expenditure

e)600 worker-hours and $6000 in capital expenditure

f)300 worker-hours and $10,000 in capital expenditure

d)900 worker-hours and $5000 in capital expenditure

Step-by-step explanation:

From the question we are told that

Daily output at a plant manufacturing chairs is approximated by the function $f(L,K) = 45\sqrt[3]{K}L^3^/^5$

Daily budget of $13,000

Average wage of an employee is $9.00 per hour

a) Generally the function $f(L,K) = 45\sqrt[3]{K}L^3^/^5$ can be use to for (a)

Mathematically solving with L=200 K=9000

$f(L=200,K=9000) = (45\sqrt[3]{9000})200^3^/^5$

f(L=200,K=9000) = 45*20.8*24

f(L=200,K=9000) = 22464

b)Generally the function $f(L,K) = 45\sqrt[3]{K}L^3^/^5$ can be use to for (b)

Mathematically solving with L=1100 K=3000

$f(L=1100,K=3000) = (45\sqrt[3]{3000})1100^3^/^5$

f(L=1100,K=3000) = 45*14.4*66.8

f(L=1100,K=3000) = 43286.4

c)Generally the function $f(L,K) = 45\sqrt[3]{K}L^3^/^5$ can be use to find (c)

Mathematically solving with L=500 K=8000

$f(L=500,K=8000) = (45*\sqrt[3]{8000})*500^3^/^5$

f(L=500,K=8000) = 45*20*41.63

f(L=500,K=8000) =37467

d)Generally the function $f(L,K) = 45\sqrt[3]{K}L^3^/^5$ can be use to find (d)

Mathematically solving with L=900 K=5000

$f(L=900,K=5000) = (45*\sqrt[3]{5000})*900^3^/^5$

f(L=900,K=5000) = 45*17.09*59.2

f(L=900,K=5000) =45577.88

e)Generally the function $f(L,K) = 45\sqrt[3]{K}L^3^/^5$ can be use to find (e)

Mathematically solving with L=600 K=6000

$f(L=600,K=6000) = (45\sqrt[3]{6000})600^3^/^5$

f(L=600,K=6000) = 45*18.17*46.4

f(L=600,K=6000) =37974

f)Generally the function $f(L,K) = 45\sqrt[3]{K}L^3^/^5$ can be use to find (e)

Mathematically solving with L=600 K=6000

$f(L=300,K=10,000) = (45*\sqrt[3]{10,000})*300^3^/^5$

f(L=300,K=10,000) = 45*21.5*30.6

f(L=300,K=10,000) = 29704.2

Therefore the function f shows maximum at L=900 K=5000

Giving the correct answer to be

d)900 worker-hours and $5000 in capital expenditure

Answer from: Quest

answer: no

step-by-step explanation:

you are only given the cost not the amount of pounds.

Answer from: Quest

step-by-step explanation:

when the line is solid:

it's either < or >

when the line is dashed:

it's either < or >

this > inequality sign means:

greater thanmore thanaboveexceeds

this < inequality sign means:

less thanfewer thanbelow

this > inequality sign means:

greater than/equal tono less thanat leastminimum of

this < inequality sign means:

less than/equal tono more thanat mostmaximum of

about the problem:

since the line is solid, that means it's either < or >

srry i'm not done ! i'll

Which inequality is represented by the graph? which test point holds true for the inequality?

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