The number of girl child per family was recorded for 1000 families with 3 children. The data obtained was as follows: [2] Number of Girls 0 1 2 3 Number of Families 112 314 382 192 Suppose a family is chosen at random, find the probability that it has: (a). At most one girl (b). More girls than boys

Step-by-step explanation:

Given

Number of Girls :      0 ---->  1 -----> 2   ------->3

Number of Families: 112 -> 314 --> 382 ---> 192

Solving (a): At most one girl

From the table, the number of families with at most one girl is: 112 + 314

i.e.

Number of Girls :      0 ---->  1

Number of Families: 112 -> 314

So, we have:

The probability is then calculated as:

Solving (b): More girls

From the table, the number of families with more girl is: 382 + 192

i.e.

Number of Girls :      -----> 2   ------->3

Number of Families: --> 382 ---> 192

So, we have:

The probability is then calculated as:

the answer is 4.8 units on e2020.

three-fourths of an hour

36÷48=0.75

0.75=