Choose the correct answer. Distance between Train 1 and Train 2 =95 miles.
Average speed of Train 1 = 45 mph.
Average speed of Train 2 60 mph.
If both trains leave at the same time and travel toward each other but on parallel tracks, in how much time will their
engines be opposite each other? (Hint: When the engines are opposite each other, together the trains will have traveled
95 miles. Their relative speed of travel is the sum of their respective speeds, or 105 mph.)
Travel time = Mhours

Step-by-step explanation:

Distance between Train 1 and Train 2=95 miles

Avg speed Train 1 = 45mph, avg speed Train 2=60mph

If both trains leave at the same time and travel toward each other but on parallel tracks, in how much time will their engines be opposite each other?

:

Let t = travel time (in hrs) until they are opposite each other

:

Like the hint said, when this happens the total distance traveled by both trains will be 95 mi.

:

write a distance equation from this fact: Dist = speed * time

;

Train 1 dist + train 2 dist = 95 mi

45t + 60t = 95

:

105t = 95

t = 95%2F105

t = .90476 hrs

or

.90476 * 60 = 54.3 min

:

:

Check solution by finding the total of the distances the two train travel

45(.90476) + 60(.90476) =

40.7 + 54.3 = 95 mi

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.