Find the equation of the line that is perpendicular to the given line and passes through the given point. Enter your answer in slope intercept for (y=mx+b) with the values of m and b given as decimals, rounded to the nearest hundredth if necessary. y=20x;(2,2) The equation is y =
Please help very urgent! :)

y = - 0.05x - 1.9

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

y = 20x ← is in slope- intercept form

with slope m = 20

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = - 0.05 , thus

y = - 0.05x + b ← is the partial equation

To find b substitute (2, - 2) into the partial equation

- 2 = - 0.1 + b ⇒ b = - 2 + 0.1 = - 1.9

y = - 0.05x - 1.9 ← equation of perpendicular line

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

the forst and 3rd

step-by-step explanation: