The choir is selling candy bars to raise money for a trip they sell each candy bar for $5 there are 7 candy bars in each box and each student in the choir can sell 2 boxes of candy bars per day there are 5 students in the choir how much money can the choir raise in 8 days?

$2800

Step-by-step explanation: Lets first figure out how much money a box of candy bars is worth. We know that each candy bar is worth $5 and that there are 7 candy bars per box. We can multiply 7*5 to figure out that each box is worth $35.

Now lets figure out how many boxes can be sold each day. Each student can sell two boxes a day. 5 students selling 2 boxes each is 5*2= 10 boxes total sold a day.

Now finally we use what we found to figure out the amount of money made per day. We know that there are 10 boxes being sold and that each box makes them $35. We just multiply 10 boxes by $35 to get $350 dollars each day.

Since they sell for 8 days we just multiply 8*$350 to get $2800.

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204