If a certain number is increased by 5, one-half of the result is three fifths of the excess of 61 over the number. find the number

see below

Step-by-step explanation:

a certain number is increased by 5, one - half of the result is three fifths of the excess of 61 over the number. Find the number.

:

1%2F2(n + 5) = 3%2F5(n+61)

Multiply both sides by 10 to get rid of the fractions, resulting in:

5(n+5) = 6(n+61)

5n + 25 = 6n + 366

5n - 6n = 366 - 25

n = -341

:

:

Check:

1%2F2(-341 + 5) = 3%2F5(-341+61)

1%2F2(-336) = 3%2F5(-280)

-168 = -168

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)