Determine the zeros of the function f(x) = (x - 2)(x + 2)(x+1)^2

x=2, x=-2, and x=-1

Step-by-step explanation:

Function: f(x)=(x-2)(x+2)(x+1)²

We can solve each one of the zeros by making the expressions (the ones in the parentheseis) equal zero.

So we have three equations:

1.(x-2)=0

2.(x+2)=0

3.(x+1)²=0

Solve.

1.x-2=0

x=2

2. x+2=0

x=-2

3. (x+1)²=(x+1)(x+1)=0

(x+1)=0

x=-1

(x+1)=0

x=-1

Since those two were the same we can just say x=-1 once.

Here are the three zeros:

x=2, x=-2, and x=-1

hope this helps!

i think it is c, not positive though

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