(2^2)^4+3^3*3^3-43+85^2/85^2+23+445 +54=?

(2^2)^4+3^3*3^3-43+85^2/85^2+23+445+54= the answer is 1465

hi! i think the answer is 1/2 : )

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: