Select the correct answer. Solve the system of equations.

y = x + 2
y = x2 + 7x + 10

A.
(-2,0) and (-4,-2)
B.
(-2,-4) and (-4,-6)
C.
(-2,-2) and (-4,0)
D.
(2,4) and (4,6)

(-2,0) and (-4,-2)

Step-by-step explanation:

The solution to the system of equations is where the two graphs cross

They cross at (-2,0) and (-4,-2)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong