A baseball team has a 20-person roster. A batting order has nine people. How many different batting orders are there

60,949,324,800

Step-by-step explanation:

We solve the above question using Permutation formula

The formula for Permutation =

nPr = n!/(n - r)!

Total Amount in a Set (n) = 20 persons

Amount in each Sub-Set (r) = 9 batting order

Hence:

20P9 = 20!/(20 - 9)!

= 60,949,324,800

Therefore, the different batting orders they would have are: 60,949,324,800

no

step-by-step explanation:

2-7=-5

7-2=5

when you combing like terms for ech expression, 5 and -5. these numbers are not equal to each other.

first, we define the variables:

x: number of years after 1950

f (x): amount of vinyl sold.

then, with the variables defined, we have:

68594 vinyl records were sold in 1958 > f (8) = 68594

91299 vinyl records were sold in 1961 > f (11) = 91299

38720 vinyl records were sold in 1952 > f (2) = 38720

161743 vinyl records were sold in 1967 > f (17) = 161743

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step-by-step explanation: