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b) In the given figure, show that triangle PQR is a right angled triangle.

Given that triangle RSP is a right triangle, then using the Pythagorean Theorem, RP = 5.  (3²+4²=5²)

Plugging the 5 in to triangle RPQ, we find that the Theorem still works for that one, which means it is a right triangle (5²+12²=13²)

Step-by-step explanation:

Given that triangle RSP is a right triangle, then using the Pythagorean Theorem, RP = 5.  (3²+4²=5²)

Plugging the 5 in to triangle RPQ, we find that the Theorem still works for that one, which means it is a right triangle (5²+12²=13²)

see explanation

Step-by-step explanation:

Using Pythagoras' identity in Δ PRS

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, then

PR² = 3² + 4² = 9 + 16 = 25 ( take the square root of both sides )

PR = = 5

Using the converse of Pythagoras in Δ PQR

If the longest side squared is equal to the sum of the squares on the other 2 sides then the triangle is right.

QR² = 13² = 169

PR² + PQ² = 5² + 12² = 25 + 144 = 169

Thus Δ PQR is a right triangle, with right angle at P

h/o/e/s mad

step-by-step explanation:

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