![= 3x = \sqrt[3]{6^{3}} = 6](/tpl/images/1010/8800/f8d1d.png)
![{x}^{3} \times {3}^{3} = {6}^{3} \\ take \: cube \: root \: on \: both \: side \ \\ \sqrt[3]{ {x}^{3} } \times \sqrt[3]{ {3}^{3} } = \sqrt[3]{ {6}^{3} } \\ x \times 3 = 6 \\ x = \frac{6}{3} \\ x = 2 \\ thnk \: you](/tpl/images/1010/8800/a5d94.png)
Given that X
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=
, find the value of X....
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