Find the orthocenter for the triangle described by each set of vertices. K (3.-3), L (2,1), M (4,-3)
Plzz help ASAP!!!

The orthocentre of the given vertices ( 2 , -3.5)

Step-by-step explanation:

Step(i):-

The orthocentre is the intersecting point for all the altitudes of the triangle.

The point where the altitudes of a triangle meet is known as the orthocentre.

Given Points are K (3.-3), L (2,1), M (4,-3)

The Altitudes are perpendicular line from one side of the triangle to the opposite vertex

The altitudes are  MN , KO , LP

step(ii):-

   Slope of the line  

The slope of MN =

The perpendicular slope of KL

                           =

The equation of the altitude

                               4y +12 = x -4

                                x - 4 y -16 = 0 ...(i)

Step(iii):-

 Slope of the line  

The slope of KO =

The perpendicular slope of LM

                           =

The equation of the altitude

The equation of the line passing through the point K ( 3,-3) and slope

m = 1/2

                                2y +6 = x -3

                             x - 2y -9 =0 ....(ii)    

Solving equation (i) and (ii) , we get

  subtracting equation (i) and (ii) , we get

                   x - 4y -16 -( x-2y-9) =0

                       - 2y -7 =0

                      -2y = 7

                        y = - 3.5

Substitute y = -3.5 in equation x -4y-16=0

               x - 4( -3.5) - 16 =0

               x +14-16 =0

                x -2 =0

                  x = 2

The orthocentre of the given vertices ( 2 , -3.5)

could you reply to this with the question so i can ?

step-by-step explanation:

what are the statements? and what do you mean by "216 2 1 6"?