The perimeter of a rectangle is 162 inches. what are the dimensions of the rectangle if the length is 7 times than 3 times the width?

3.68 inches × 77.28 inches

Step-by-step explanation:

Given that,

The perimeter of a rectangle is 162 inches.

Let the width is b.

ATQ,

Length = 7 times than 3 times the width

l = 7(3b) = 21b ...(1)

The perimeter of a rectangle is given by :

P = 2(l+b)

Put all the values,

162 = 2(21b+b)

81 = 22b

b = 3.68 inches

Put the value of b in equation (1)

l = 21b

= 21 (3.68)

= 77.28 inches

Hence, the dimensions of the rectangle are 3.68 inches × 77.28 inches

16

step-by-step explanation:

2 x 40 = 80

80/5

= 16

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3