Mathematics, 01.01.2021 06:10 astultz309459

What is the solution of StartRoot negative 4 x EndRoot = 100?

Answers: 3

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Answers

Answer from: dozsyerra

The given can be solved by simplifying the equation to make x the subject

of the equation.

The solution of the equation is x = -2,500

Reasons:

The equation is; √(-4·x) = 100

The above equation can be expressed as follows;

$\displaystyle \sqrt{-4 \cdot x} = \left(-4 \cdot x \right)^{\frac{1}{2} } = \mathbf{100}$

By squaring both sides, we get;

$\displaystyle \mathbf{ \left(-4 \cdot x \right)^{\frac{1}{2} \times 2 }} = 100^2$

Which gives;

$\displaystyle \left(-4 \cdot x \right)^{\frac{1}{2} \times 2 } = \left(-4 \cdot x \right)^{1 }= -4 \cdot x = 100^2$

$\displaystyle -4 \cdot x = 100^2 = 100 \times 100 = \mathbf{10,000}$

$\displaystyle -4 \cdot x = 10,000$

Dividing both sides by -4 gives;

$\displaystyle x = \mathbf{ \frac{10,000}{-4} } = -2,500$

Therefore'

x = -2,500

The solution of the equation √(-4·x) = 100 is; x = -2,500

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Answer from: Naysa150724

x=-2500

Step-by-step explanation:

$\sqrt{-4x} =100\\\\(\sqrt{-4x})^2=100^2\\\\-4x=10,000\\\\x=-\frac{10000}{4}\\\\x=-2500$

Answer from: Quest

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Answer from: Quest

x= 1

step-by-step explanation: convert 5\frac{11}{12}5

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{5\times 12+11}{12}3.25+0.5x+1

5×12+11

2 simplify 5\times 125×12 to 6060

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{60+11}{12}3.25+0.5x+1

60+11

3 simplify 60+1160+11 to 7171

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{71}{12}3.25+0.5x+1

4 simplify \frac{5}{6}x

x to \frac{5x}{6}

3.25+0.5x+1\frac{1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+1

5 convert 1\frac{1}{3}1

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+\frac{1\times 3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

1×3+1

6 simplify 1\times 31×3 to 33

3.25+0.5x+\frac{3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3+1

7 simplify 3+13+1 to 44

3.25+0.5x+\frac{4}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

8 simplify 3.25+0.5x+\frac{4}{3}+\frac{5x}{6}3.25+0.5x+

to \frac{13.75}{3}+\frac{4x}{3}

13.75

\frac{13.75}{3}+\frac{4x}{3}=\frac{71}{12}

13.75

9 simplify \frac{13.75}{3}

13.75

to 4.5833334.583333

4.583333+\frac{4x}{3}=\frac{71}{12}4.583333+

10 subtract 4.5833334.583333 from both sides

\frac{4x}{3}=\frac{71}{12}-4.583333

−4.583333

11 simplify \frac{71}{12}-4.583333

−4.583333 to \frac{4}{3}

\frac{4x}{3}=\frac{4}{3}

12 multiply both sides by 33

4x=\frac{4}{3}\times 34x=

×3

13 simplify \frac{4}{3}\times 3

×3 to \frac{12}{3}

4x=\frac{12}{3}4x=

14 simplify \frac{12}{3}

to 44

4x=44x=4

15 divide both sides by 44

x=1

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